Answer:
a, 1.775s
b, 17.04μC
c, 1.28s
Explanation:
Given
R = 1.25MΩ
C = 1.42µF
ε = 12.0 V
q = 8.78 µC
Time constant, τ = RC
τ = (1.25*10^6) * ( 1.42*10^-6)
τ = 1.775s
q• = εC
q• = 12 * 1.42*10^-6
q• = 17.04*10^-6C
q• = 17.04μC
Time t =
q = q• [1 - e^(t/τ)]
t = τIn[q•/(q•-q)]
t = 1.775In[17.04μC/(17.04μC-8.78μC)]
t = 1.775In(2.06)
t = 1.775*0.723
t = 1.28s
<span>Higher temperature means greater kinetic energy, which means the warmer block has greater thermal energy.
hoped this helped</span>
Answer:
K = 1800 kJ
Explanation:
Given that,
The speed of the object, v = 30 m/s
Mass of the object, m = 4000 kg
We need to find the kinetic energy of the object. The formula for the kinetic energy is given by :
So, the required kinetic energy is equal to 1800 kJ.
Answer:
Explanation:
mass of sled, m = 22 kg
Force of pull, F = 31 N
distance move, d = 53 m
Angle between force and distance, θ = 40°
The formula for the work done is
W = F x d x Cos θ
W = 31 x 53 x cos 40
W = 1258.6 J