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2 years ago

The system has how many solutions?

Mathematics

2 answers:

mafiozo [28]2 years ago

4 0

Answer:

1 solution

Step-by-step explanation:

It's only 1, because the two lines intersect in one spot only.

Nostrana [21]2 years ago

3 0

Answer:

It should have a Infinite Solution

Step-by-step explanation:

My reason is that if those lines on the graph have the arrows that means it could go on forever which means it's infinite, I'm talking about that X looking line thing lol

Idk the question is kinda confusing

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Please show your work how you solved this step by step ! Please answer this !!

erastovalidia [21]

Answer:

2x^2

Step-by-step explanation:

8 0

2 years ago

I don’t understand please help me and give the answer

barxatty [35]

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2 years ago

Solve x - 6x = 40 by factoring. What is the solution?

marta [7]

Answer:

x=-8

Step-by-step explanation:

collect like terms

-5x=40

divide both sides of the equation by -5

so the answer would be x=-8

7 0

2 years ago

Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Thus the given expression is simplified

8 0

2 years ago

Plz help, I don't know how to do this

exis [7]

Once you complete the square the equation is (x+3)^2 + (y - 8)^2 = 64
The center is (-3,8)
Radius is 8
A. False
B. True
C. False

3 0

2 years ago