F(x)=2x^2-x-6
Factoring:
f(x)=2(2x^2-x-6)/2=(2^2x^2-2x-12)/2=[(2x)^2-(2x)-12]/2
f(x)=(2x-4)(2x+3)/2=(2x/2-4/2)(2x+3)→f(x)=(x-2)(2x+3)
g(x)=x^2-4
Factoring
g(x)=[sqrt(x^2)-sqrt(4)][sqrt(x^2)+sqrt(4)]
g(x)=(x-2)(x+2)
f(x)/g(x)=[(x-2)(2x+3)] / [(x-2)(x+2)
Simplifying:
f(x)/g(x)=(2x+3)/(x+2)
Answer: Third Option (2x+3)/(x+2)
first, you would rearrange the equation so that like terms were next to each other.
7y - 5y - x2 + 2x2 +3x - 17x
then you would reduce the equation based on like terms
2y + x2 - 14x
then simply rearrange the equation to get the answer, which is <u>B</u>
Answer:
Yeah
Step-by-step explanation:
1. understand time management
2. Value time.
3. use time wisely
4. take advantage of the opportunity of extra time.
5. smile, it's all linear! : )