Answer:
C/2pi = r
Step-by-step explanation:
C = 2 pi r
divide with 2 pi on both sides to solve for r
C/2pi = r
<h3><em><u>Simplify -3y+2x-5y-7x is:</u></em></h3><h3>-8y - 5x</h3>
<em><u>Solution:</u></em>
<em><u>Given that, we have to simplify</u></em>
We can simplify the above expression by combining the like terms
Like terms are terms that has same variable ( with same exponent) with same or different coefficient
From given,
Here, like terms are -3y and -5y
And 2x and -7x
Group the like terms
Combine the like terms
Thus the given expression is simplified
Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.
I would say 1 but I feel like that wouldn't help you and that's all I know, plus I don't want to look it up because of the policy. I wanna help tho, so that's all I'm gonna say (please don't get mad at me)