Answer:
Step-by-step explanation:
Given is a differential equation as
Divide this by t to get in linear form
This is of the form
y' +p(t) y = Q(t)
where p(t) = 1/t
So solution would be
siubstitute y(1) = 16
Answer:
The points for the given to linear equations is (5 , - 2) and (5 , - 1)
The points is plotted on the graph shown .
Step-by-step explanation:
Given as :
The two linear equation are
y = x - 1 ...........1
y = x - 6 ...........2
Now, Solving both the linear equations
Put the value of y from eq 2 into eq 1
I.e x - 6 = x - 1
Or, x + x = 6 - 1
Or, x = 5
or, x = 5
∴ x = 5
Now, Put the value of x in eq 1
So, y = x - 1
Or, y = × 5 - 1
or, y = - 1
Or, y = - 1 - 1
I.e y = -2
So, For x = 5 , y = - 2
Point is ( , ) = (5 , - 2)
Again , put the value of x in eq 2
So, y = x - 6
Or, y = × 5 - 6
Or, y = - 6
Or, y = 4 - 6
I.e y = - 2
So, For x = 5 , y = - 2
Point is ( , ) = (5 , - 2)
Hence, The points for the given to linear equations is (5 , - 2) and (5 , - 2)
The points is plotted on the graph shown . Answer
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Answer:
See proof below
Step-by-step explanation:
We have to verify that if we substitute in the equation the equality is true.
Let's substitute first in the right hand side:
Now we use the distributive laws. Also, note that (this also works when the power is n-2).
then the sequence solves the recurrence relation.