Answer:the repair shop is 5km from her house.
Step-by-step explanation:
Let x represent the distance of the repair shop from her house.
Let y represent Emily's speed when riding.
Distance = speed × time
It took Emily 25 min to ride her bike to the repair shop. Converting 25 min to hours, it becomes 25/60 = 5/12 hours.
Distance covered,
x = y × 5/12 = 5y/12
It took her 1h 15 min to walk back home. Converting to hours, it becomes 1 + 15/60 = 1 1/4 = 5/4
If she can ride her bike 8km/h faster than she can walk, it means that her speed while walking would be y 8 8
Therefore,
Distance covered,
x= 5/4(y - 8) = (5y - 40)/4
Since the distance remains the same, then
5y/12 =(5y - 40)/4
Crossmultiplying, it becomes
5y × 4 = 12(5y - 40)
20y = 60y - 480
60y - 20y = 480
40y = 480
y = 480/40 = 12
x = 5y/12 = 5 × 12/12 = 5 km
Answer:
Step-by-step explanation:
So we have the expression:
And we wish to factor it.
First, let's make a substitution. Let's let u be equal to x². Therefore, our expression is now:
This is a technique called quadratic u-substitution. Now, we can factor in this form.
We can use the numbers -3 and -2. So:
For the first two terms, factor out a u.
For the last two terms, factor out a -3. So:
Grouping:
Now, substitute back the x² for u:
And this is the simplest form.
And we're done!
8.9-3.3j=-2.2j+2.3
add 3.3j to both sides
8.9=1.1j+2.3
subtract 2.3 from both sides
6.6=1.1j
divide both sides by 1.1
6=j
To find the amount of fabric for one side of the purse you will find the area of the trapezoidal space that is created. The latch is on the top, so the 2 in is not necessary information.
A = 1/2 h(b1 + b2)
1/2 x 13 x (10 + 16)
A = 169 square inches of fabric will be needed.
Answer:
Option (2). 1
Step-by-step explanation:
Coordinates of point A, B, C and D are,
A(-4, 4), B(-2, 4), C(-2, 1) and D(-4, 3).
Quadrilateral ABCD when rotated 90° clockwise about the origin,
Rule for the rotation of the vertices,
(x, y) → (y, -x)
Following the rule of rotation coordinates of the image points,
A(-4, 4) → A'(4, 4)
B(-2, 4) → B'(4, 2)
C(-2, 1) → C'(1, 2)
D(-4, 3) → D'(3, 4)
Since all image points have the positive coordinates (x and y coordinates), image quadrilateral A'B'C'D' will be located in 1st quadrant.
Option (2) is the correct option.