Answer:
The upper limit of the 95% confidence interval is:
C.I_u = 200 + (58.8/)
Step-by-step explanation:
The formula is given as:
C.I = μ ± Z*σ/
The upper limit => C.I_u = μ + Z*σ/
The lower limit => C.I_l = μ - Z*σ/
The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.
The upper limit => C.I_u = 200 + 1.96*(30/)
= 200 + (1.96*30)/
= 200 + 58.8/
It's 0 because 10+10 = 20 then subtract 20 and you get zero.
Answer is 86.47 cm hope helped
(√3 + √11)² + (√3 - √11)²
- (a+b)² = a² + b² + 2ab
- ( a - b )² = a² + b² - 2ab
<em>Now </em><em>,</em>
(√3 + √11)² + (√3 - √11)²
(3 + 11 + 2√3√11)+ (3 +11 - 2√3√11)
14 + 2√33+ 14 - 2√33
14 + 14 = 28
Hence , The value of (√3 + √11)² + (√3 - √11)² is 28 .