The order will be IV, III, I, and II.
<h2>Polynomial</h2>
Polynomial is an algebraic expression that consists of variables and coefficients. Variable are called unknown. We can apply arithmetic operations such as addition, subtraction, etc. But not divisible by variable.
Given
I. x + 2xyz
II. 9x³y²
III. 18x² + 5ab - 6y
IV. 4
+ 3x² - x - 4
<h3>To find </h3>
The polynomial expressions from least to greatest are based on their degree.
<h3>How to organize?</h3>
4 + 3x² - x - 4 is a biquadratic ploynolmial.
18x² + 5ab - 6y is a cubic polynomial.
x + 2xyz is a quadratic polynomial.
9x³y² is a monomial polynomial.
So the order will be IV, III, I, and II.
More about the polynomial link is given below.
brainly.com/question/17822016
Answer:
<em>Martin saved $75 on the television because of the sale</em>
Step-by-step explanation:
<u>Equations</u>
Let's call x=the original price of the television (before discount).
The television had been on sale for 25% off, this means the discount was:
25% of x = 
= 0.25x
The sale price was the original price minus the discount:
x - 0.25x = 0.75x
This is what Martin paid, thus:
0.75x = 225
Dividing by 0.75:
x = 225 / 0.75
x = $300
The original price of the television was $300, and the discount was:
0.25*$300 = $75
Martin saved $75 on the television because of the sale
12
x 10
______
120
it's pretty simply,sorry if I got it wrong,i'm kinda tired<span />
Answer:
n = 60.22
Step-by-step explanation:
Hello
To find Sn, we need to draw out equations for each a₇ and a₁₉
In an arithmetic progression,
Sn = a + (n-1)d
Where Sn = sum of the A.P
a = first term
d = common difference
a₇ = 32
32 = a + (7-1)d
32 = a + 6d ........equation (i)
a₁₉ = 140
140 = a + (19-1)d
140 = a + 18d .........equation (ii)
Solve equation (i) and (ii) simultaneously
From equation (i)
32 = a + 6d
Make a the subject of formula
a = 32 - 6d .....equation (iii)
Put equation (iii) into equation (ii)
140 = (32 - 6d) + 18d
140 = 32 - 6d + 18d
Collect like terms
140 - 32 = 12d
12d = 108
d = 108 / 12
d = 9
Put d = 9 in equation (i)
32 = a + 6(9)
32 = a + 54
a = 32 - 54
a = -22
When Sn = 511
Sn = a + (n - 1)d
Substitute and solve for n
511 = -22 + (n-1) × 9
511 = -22 + 9n - 9
511 = -31 + 9n
511 + 31 = 9n
542 = 9n
n = 542 / 9
n = 60.22
Answer:
Step-by-step explanation:
The time intervals are [0.00, 0.10], [0.10, 0.30], and [0.30, 0.60].
The rate of change in each interval is the slope of the line between the endpoints:
m = [f(b) − f(a)] / (b − a)
Filling out the table:
![\left[\begin{array}{ccc}Time (s)&Height (ft)&Rate\ of\ change(ft/s)\\0.00&96.44\\&&\frac{97.60-96.44}{0.10-0.00}=11.6 \\0.10&97.60\\&&\frac{98.57-97.60}{0.30-0.10}=4.85\\0.30&98.57\\&&\frac{98.30-98.57}{0.60-0.30}=-0.90\\0.60&98.30\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7DTime%20%28s%29%26Height%20%28ft%29%26Rate%5C%20of%5C%20change%28ft%2Fs%29%5C%5C0.00%2696.44%5C%5C%26%26%5Cfrac%7B97.60-96.44%7D%7B0.10-0.00%7D%3D11.6%20%5C%5C0.10%2697.60%5C%5C%26%26%5Cfrac%7B98.57-97.60%7D%7B0.30-0.10%7D%3D4.85%5C%5C0.30%2698.57%5C%5C%26%26%5Cfrac%7B98.30-98.57%7D%7B0.60-0.30%7D%3D-0.90%5C%5C0.60%2698.30%5Cend%7Barray%7D%5Cright%5D)
The intervals are already in order from greatest to least. Simply reverse the order to get least to greatest:
[0.30, 0.60]
[0.10, 0.30]
[0.00, 0.10]
