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2 years ago

What is the radius of the circle given by the equation below?

Mathematics

1 answer:

lapo4ka [179]2 years ago

3 0

Answer:

A. 3

Step-by-step explanation:

Hello

X^2 + 8X + (8/2)^2 + Y^2 + 14Y + (14/2)^2 = (8/2)^2 + (14/2)^2-56

(X+4)^2 + (Y+7)^2 = 16 + 49 - 56

(X+4)^2 + (Y+7)^2 = 9

Then

The radius for that circle is 3

Best regards

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2 years ago

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2 years ago

Given: F(x) = 2x2+ 1, G(x) = 2x - 1, H(x) = x F(3) + G(4) - 2H(5) = 16 26 34

Roman55 [17]

Answer:

Step-by-step explanation:

Put the numbers where the variables are and evaluate:

F(3) = 2(3)^2 +1 = 19

G(4) = 2(4) -1 = 7

H(5) = 5

Then the desired sum is ...

F(3) +G(4) -2H(5) = 19 +7 -2(5) = 16

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2 years ago

Someone help me out with this

Trava [24]

Answer:

4x = 20

x = 5

Step-by-step explanation:

Have a nice day!

8 0

2 years ago

Solve the equation by factoring.

Delicious77 [7]

Factorizing an expression involves writing the expression in simpler forms

The values of z are $z = \frac 15$ or $z=4$

The equation is given as:

$5z^2 - 21z + 4 = 0$

Expand the equation

$5z^2 - 20z -z + 4 = 0$

Factorize the expression:

$5z(z - 4) -1(z - 4) = 0$

Factor out z - 4

$(5z - 1)(z - 4) = 0$

Split

$5z -1 = 0$ or $z - 4 = 0$

Solve for z

$z = \frac 15$ or $z=4$

Hence, the values of z are $z = \frac 15$ or $z=4$