No question is asked so I'm not sure what you are looking for but below I calculated the point where the two equations intersect:
y - x = 4 → y = x + 4
y = - x² + 6x
x + 4 = - x² + 6x
x² - 5x + 4 = 0
(x - 4)(x - 1) = 0
x = 4, x = 1
when x = 4, then y = x + 4 = 4 + 4 = 8 → (4,8)
when x = 1, then y = x + 4 = 1 + 4 = 5 → (1,5)
The line and parabola intersect at two points: (4,8) and (1,5)
Area of each side triangle is 1/2*8*15 = 60. There are 5 of them so the triangles have surface area 300. the pentagon's area 1/2*apothegm*sidelength*sides = 1/2*5.5*8*5 = 110. The total area is therefore 300+110 = 410
Answer:
Solution given:
Volume of cone=⅓πr²h
Volume of cylinder=πr²h
1.
volume =πr²h=π*(10/2)²*6=<u>471.23mm³</u>
2.
Volume =πr²h=π*8*12.5=<u>314.16in³</u>
3.
volume =⅓πr²h=⅓*π*4²*3=<u>5</u><u>0</u><u>.</u><u>2</u><u>6</u><u>c</u><u>m</u><u>³</u>
4.
Volume =⅓πr²h=⅓*π*(8/2)²*12=<u>2</u><u>0</u><u>1</u><u>.</u><u>0</u><u>6</u><u>i</u><u>n</u><u>³</u>
Answer:
The values of so that have vertical asymptotes are , , , , .
Step-by-step explanation:
The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is . Then, the vertical asymptotes associated with function cosecant are located in the values of of the form:
,
In other words, the values of so that have vertical asymptotes are , , , , .
Answer:
i believe the answer is 15 milliliters
Step-by-step explanation: