Answer:
-4.71 m/s
Explanation:
Given:
y₀ = 1.13 m
y = 0 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2a (y − y₀)
v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.13 m)
v = -4.71 m/s
Explanation:
the object will begin to move
Answer:
The maximum amount of work is
Explanation:
From the question we are told that
The temperature of the environment is
The volume of container A is
Initially the number of moles is
The volume of container B is
At equilibrium of the gas the maximum work that can be done on the turbine is mathematically represented as
Now from the Ideal gas law
So substituting for in the equation above
Where R is the gas constant with a values of
Substituting values we have that
The density value 3.291 g/ml (gram / milliliter) in words is "three point two nine one g/ml (gram / milliliter)".
=)
Answer:
depende de que fenómenos nos referimos de acuerdo al los cuerpos de formación puede aver movimiento contante