What is the weight of a 75 kg. Mass?

Jasper made a list of the properties of electromagnetic waves. Identify the mistake in the list.

ch4aika [34]

Answer:

B. Line 2 has a mistake

Explanation:

1. All electromagnetic waves are made of both electric and magnetic fields (hence the name electromagnetic).

2. All electromagnetic waves are transverse, and not longitudinal.

3. All electromagnetic waves can travel through space because they do not need particles to travel (like sound waves).

4. Electromagnetic waves all travel at the speed of light (299 792 458 m/s).

3 0

2 years ago

A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 12

andrew-mc [135]

Answer:

450 g/mol

Explanation:

To solve the problem the problem, it is necessary to use Graham's Law of effusion

$\sqrt{\frac{M_{1} }{M_{2} } } = \frac{t_{1} }{t_{2}} \\\\{\frac{M_{1} }{32g/mol} = (\frac{120s}{32s} )^{2} = 450g/mol$

This answer is consistent with what we know. A heavier gas will require more time to effuse than a lighter gas

3 0

2 years ago

Use the tabulated half-cell potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25

Llana [10]

Answer: Thus the value of equilibrium constant for the balanced redox reaction at 25°C is $8.9\times 10^{-73}$

Explanation:

$2Al(s)+3Mg^{2+}(aq)\rightarrow 2Al^{3+}(aq)+3Mg(s)$

Here Al undergoes oxidation by loss of electrons, thus act as anode. magnesium undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0_{[Mg^{2+}/Mg]}= -2.37V$

$E^0_{[Al^{3+}/Al]}=-1.66V$

$E^0=E^0_{[Mg^{2+}/Mg]}- E^0_{[Al^{3+}/Al]}$

$E^0=-2.37V-(-1.66)=-0.71$

The standard emf of a cell is related to Gibbs free energy by following relation:

$\Delta G=-nFE^0$

$\Delta G$ = gibbs free energy

n= no of electrons gained or lost = 6

F= faraday's constant

$E^0$ = standard emf

$\Delta G=-6\times 96500\times (-0.71)=411090J$

The Gibbs free energy is related to equilibrium constant by following relation:

$\Delta G=-2.303RTlog K$

R = gas constant = 8.314 J/Kmol

T = temperature in kelvin = $25^0C=25+273=298K$

K = equilibrium constant

$\Delta G=-2.303RTlog K$

$411090=-2.303\times 8.314\times 298\times logK$

$K=8.9\times 10^{-73}$

Thus the value of equilibrium constant for the balanced redox reaction at 25°C is $8.9\times 10^{-73}$

3 0

2 years ago

When polymers are broken down what are the monomers used for

Lapatulllka [165]

When polymers are broken down into monomers, <u>the body uses those monomers for a number of activities. Some of them include protein construction and respiration. </u>

For proteins, the monomers are amino acids. Polymerization occurs at ribosomes. Usually about 20 types of amino acid monomers are used to produce proteins.

<em>The process of polymers breaking down to monomers is called hydrolysis.</em>

5 0

2 years ago

A gas is originally at a temperature of 23.13 degrees C. What temperature must it be heated to triple its volume with constant p

alexgriva [62]

Initial temperature= T1 = 23.13 °C
Initial Volume= V1 = V

Final Volume= V2 = 3V
Final temperature= T2 = ?
According to general gas eq.
P1*V1/T1 = P2*V2/T2

As, the pressure is constant
So. eq. become
V1/T1 = V2/T2
V/23.13 = 3V/T2
T2= 69.39 °C

6 0

2 years ago