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2 years ago

when obtaining energy, why mushrooms are more like elephants eating and not like dandelions absorbing sunlight.

Chemistry

1 answer:

Julli [10]2 years ago

6 0

Answer:

Because they lack chlorophyll (a green pigment in plants that helps them trap sunlight, used to manufacture their food through photosynthesis)

Explanation:

Mushrooms are heterotrophs. They are not plants or autotrophs. Mushrooms, just like every living thing that exists need energy in order to live. Only plants, or autotrophs, can directly use energy from the sun (the ultimate energy) to make food. Those organisms that cannot harness the sun's energy are known as heterotrophs. Mushrooms are fungi (belong to kingdom Fungi) and are heterotrophs because they decompose and consume nutrients from the soil. They are not green so they cannot photosynthesis due to lack of chlorophyll.

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How do you find the metal “M”

Elodia [21]

M = Sr (strontium)

Step 1. Calculate the moles of CO_2.

Moles of CO_2 = 0.395 g CO_2 × (1 mol CO_2/44.01 g CO_2)

= 0.008 975 mol CO_2

Step 2. Calculate the moles of MCO_3.

Moles of MCO_3 = 0.008 975 mol CO_2 × (1 mol MCO_3/1 mol CO_2)

= 0.008 975 mol MCO_3

Step 3. Calculate the molar mass of MCO_3

MM = grams/moles = 1.324 g/0.008 75 mol = 147.5 g/mol

Step 4. Calculate the atomic mass of M

M_r = x + 12.01 + 3×16.00 = x + 60.01 = 147.5

x = 147.5 – 60.01 = 87.5

Step 5. Identify M.

The element with the closest atomic mass is Sr (A_r = 87.6).

∴ M = Sr and the compound is SrCO_3.

5 0

3 years ago

Plants and animals need to protect themselves to survive. Select the statement that best describes the adaptions of animals and

saul85 [17]

I need points lol sorry for wasting ur time we

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2 years ago

Given the data calculated in Parts A, B, C, and D, determine the initial rate for a reaction that starts with 0.45 M of reagent

sladkih [1.3K]

Answer:

$\large\boxed{\large\boxed{0.0014M/s}}$

Explanation:

From the table, first find the order of reaction, then find the rate constant, write the rate equation, and, finally, subsititue the data for the reaction that starts with 0.45M of reagent A and 0.90 M of reagents B and C.

1. Table

Trial [A] (M) [B] (M) [C] (M) Initial rate (M/s)

1 0.20 0.20 0.20 6.0×10⁻⁵

2 0.20 0.20 0.60 1.8×10⁻⁴

3 0.40 0.20 0.20 2.4×10⁻⁴

4 0.40 0.40 0.20 2.4×10⁻⁴

2. Orders

a) From trials 3 and 4 you learn that the initial concentration of B does not change the change teh rate of the reaction. Hence the order with respect to [B] is 0.

b) From trials 1 and 2 you learn that when the concentration of C is tripled the rate of reaction is also tripled:

0.60 / 0.2 = 3, and

1.8×10⁻⁴ / 6.0×10⁻⁵ = 3

Hence, the order with respect to C is 1.

c) From trials 1 and 3 you get:

0.40/0.2 = 2

2.4×10⁻⁴ / 6.0×10⁻⁵ = 4

Which means that when the concentration of A is doubled, the rate of the reaction is quadruplicated. Hence, the order of the reaction with respect to A is 2.

3. Rate equation

Ther orders are:

$a=2\\\\b=0\\\\c=1$