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2 years ago

6

A car travels 30 1/5 miles in 2/3 of an hour

1 answer:

Nimfa-mama [501]2 years ago

8 0

Send me the pics of y’all in my brothers friends and family friends

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Hoe do i get the answer? what do i do ??

HACTEHA [7]

That equal 1 because they are the same

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2 years ago

Read 2 more answers

How to find the Perimeter?

SOVA2 [1]

Answer:

8+2 $\sqrt{20\\}\\$

Step-by-step explanation:

2+2+2+2+ $\sqrt{20\\}\\$ + $\sqrt{20\\}\\$ =8+2 $\sqrt{20\\}\\$

4^2+2^2=h^2

20=h^2

h= $\sqrt{20\\}\\$

7 0

2 years ago

Evaluate: |18|<br> A:1/18<br> B:-1/-18<br> C:-18<br> D18

masya89 [10]

Answer will be D. Absolute value can never be negative.

4 0

2 years ago

Please help and explain

lakkis [162]

Answer:

look at the picture I sent

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2 years ago

Two shooters, Rodney and Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark

Sedaia [141]

Complete Question

Answer:

a

$SE = 0.66}$

b

$-3.29 < \mu_1 - \mu_2 < -0.70$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The first sample mean is $\= x _1 = 8$

The second sample mean is $\= x _2 = 10$

The first variance is $v_1 = 0.25$

The first variance is $v_2 = 0.55$

Given that the confidence level is 95% then the level of significance is 5% = 0.05

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the first standard deviation is

$\sigma_1 = \sqrt{v_1}$

=> $\sigma_1 = \sqrt{0.25}$

=> $\sigma_1 = 0.5$

Generally the second standard deviation is

$\sigma_2 = \sqrt{v_2}$

=> $\sigma_2 = \sqrt{0.55}$

=> $\sigma_2 = 0.742$

Generally the first standard error is

$SE_1 = \frac{\sigma_1}{\sqrt{n} }$

$SE_1 = \frac{0.5}{\sqrt{60} }$

$SE_1 = 0.06$

Generally the second standard error is

$SE_2 = \frac{\sigma_2}{\sqrt{n} }$

$SE_2 = \frac{0.742}{\sqrt{60} }$

$SE_2 = 0.09$

Generally the standard error of the difference between their mean scores is mathematically represented as

$SE = \sqrt{SE_1^2 + SE_2^2 }$

=> $SE = \sqrt{0.06^2 +0.09^2 }$

=> $SE = 0.66}$

Generally 95% confidence interval is mathematically represented as

$(\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } * SE) < \mu_1 - \mu_2 < (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } * SE)$

=> $(8 -10) -(1.96 * 0.66) < \mu_1 - \mu_2 < (8-10) +(Z_{\frac{\alpha }{2} } * 0.66)$

=> $-3.29 < \mu_1 - \mu_2 < -0.70$

5 0

2 years ago