Answer:
Step-by-step explanation:
we know that distance d from the focus to P should be the same to the distance from P to the directrix
(x-h)^2=4p(y-k)
we need to find the y coordinate,
x is the same from focus, 3
y=(3, (4+2)/2)=(3,3)
we find p now by subtracting the y from the focus from the y that we just found
p=4-3=1
again (x-h)^2=4p(y-k), p=1
(x-3)^2=4(1)(y-3)
(x-3)^2=4(y-3), (x-3)^2=4y-12
simplify
4y=(x-3)^2+12
y=((x-3)^2)/4 + 3
May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
(-3,2)))))))))))))))))))))))))))))))))))
B - 3/4 = 7/10
add 3/4 to both sides to isolate the b
b = 7/10 + 3/4
b = 28/40 + 30/40
b = 58/40
b = 1 18/40
b = 1 9/20
