Answer:
26 degrees Celcius
Step-by-step explanation:
The minimum temperature is -11
The maximum temperature is 15
to get from -11 to 0: add 11
to get from 0 to 15: add 15
11+15 = 26
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:
where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:
Hence, the half life of the sample of phosphorus-32 is
On Part A you have to subtract $2.39-$1.99. Then in Part B you have to multiply $4.50 by 2. And then I think you have to add $3.79 when u are done multiplying.
Can you please take a picture of the question?