The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
To find the slope and the -intercept of the line, first write the function as an equation, by substituting for
y=10
y=0x+10
y=0x+10 , m=0
y=0x+10 , m=0 , b=10
m=0 , b=10
The slope of the line is m=0 and the y-intercept is b=10
Answer:
Step-by-step explanation:
A line that passes through the point (4,-6) has a slope of 5/-4. Which of the following gives the equation of the line?
With the slope of 5/-4, and the ordered pair (4,-6) :
let m = 5/-4 (slope),
x1 = 4
y1 = -6
We can use those given values into the point-slope formula:
y - y1 = m(x - x1)
Plugging in those values will give you the answer:
y - (-6) = (x - 4)
Distribute into the terms inside the parenthesis:
y + 6 = + 5
Subtract 6 from both sides to isolate y:
y + 6 - 6 = +5 - 6
The equation of the line in slope-intercept form is:
The answer to your question is false