All categories

2 years ago

What are all real numbers greater than or equal to 0 called?

Mathematics

1 answer:

7nadin3 [17]2 years ago

8 0

Answer:

Postitive numbers

Step-by-step explanation:

You might be interested in

An equation is shown below: 3(2x − 7) = 9

Katen [24]

Answer:

1 solution

Step-by-step explanation:

3(2x-7)=9

dustribute: (3)(2)+(3)(-7x)=9

6+-21x=9

subtract 6 from both sides: -21x=3

Divide both sides by -21: x=-1/7

so your 1 solution is x = - 1/7

3 0

1 year ago

A polynomial function has a zero at 4 (multiplicity 3) and 0 (multiplicity 1). write a function in standard form

kozerog [31]

Y=3x(x-4)
Hope this helps!!

6 0

2 years ago

Read 2 more answers

Simplify the square root of 3 times the fifth root of 3.

bogdanovich [222]

Answer:

<h2><em>Three to the three fifths power.</em></h2>

Step-by-step explanation:

The given expression is

$\sqrt{3\sqrt[5]{3} }$

To simplify this expression, we have to use a specific power property which allow us to transform a root into a power with a fractional exponent, the property states:

$\sqrt[n]{x^{m}}=x^{\frac{m}{n}}$

Applying the property, we have:

$\sqrt{3\sqrt[5]{3}}=\sqrt{3(3)^{\frac{1}{5}}}=(3(3)^{\frac{1}{5}})^{\frac{1}{2}}$

Now, we multiply exponents:

$(3(3)^{\frac{1}{5}})^{\frac{1}{2}}\\3^{\frac{1}{2}}3^{\frac{1}{10}}$

Then, we sum exponents to get the simplest form:

$3^{\frac{1}{2}}3^{\frac{1}{10}}=3^{\frac{1}{2}+\frac{1}{10}} =3^{\frac{10+2}{20}}=3^{\frac{12}{20}} \\\therefore \sqrt{3\sqrt[5]{3}}=3^{\frac{3}{5} }$

Therefore, the right answer is <em>three to the three fifths power.</em>

3 0

2 years ago

Read 2 more answers

Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

3 0

2 years ago

Round 67,000 to the ten thousand

Sveta_85 [38]

ANSWER:

70, 000

67, 000 rounded to the nearest ten thousand is: 70, 000.

EXPLANATION:

As we are rounding the number to the nearest ten thousand, we will look at the thousand digit of the number in order to decide whether to round the number up or down. As the thousand digit is 7, we must round the ten thousand digit up meaning that the 6 would become a 7. Therefore, the answer would be 70, 000.

7 0

2 years ago

Read 2 more answers