A soccer ball kicked from the ground with an initial velocity of 32 ft/s is given by the function

Mathematics

2 answers:

Greeley [361]2 years ago

6 0

Answer:

In words the answer is between t=0 and t=2.

In interval notation the answer is (0,2)

In inequality notation the answer is 0<t<2

Big note: You should make sure the function I use what you meant.

Step-by-step explanation:

I hope the function is h(t)=-16t^2+32t because that is how I'm going to interpret it.

So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.

0=-16t^2+32t

0=-16t(t-2)

So at t=0 and t=2

So the ball is in the air between t=0 and t=2

Interval notation (0,2)

Inequality notation 0<t<2

Scorpion4ik [409]2 years ago

5 0

Answer:

Its C on edg

Step-by-step explanation:

follow my ifunny "dankmemehistory"

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Which of these choices show a pair of equivalent expressions? CHECK ALL THAT APPLY

aleksklad [387]

Answer:

Option C & D

Step-by-step explanation:

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FACTS TO KNOW BEFORE SOLVING :-

Lets say there's an expression $x^{\frac{a}{b} }$ .

It can be also written it as → $(\sqrt[b]{x} )^{a}$ and vice-versa.

__________________________________________________________

Lets come to the question.

In option A , $7^{\frac{5}{7} }$ can be also written as $(\sqrt[7]{7} )^{5}$ . But it doesn't match with the other expression given. Hence they are not equivalent expressions.

In option B , $6^{\frac{2}{7} }$ can be also written as $(\sqrt[7]{6} )^{2}$ . But it doesn't match with the other expression given. Hence they are not equivalent expressions.