The standard form of five and fiffty hundredths is

Mathematics

1 answer:

mash [69]2 years ago

6 0

Answer:

You could do 5 x 1 = 5

And for fifty, 5 x 10 = 50

Step-by-step explanation:

Standard form is basically a big or small equation of the numbers

standard form is the usual way of writing numbers in decimal notation, i.e. standard form = 876, expanded form = 800 + 70 + 6, written form = eight hundred seventy six

Hope it helped :)

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How many times does 32 go into 204

jeka94

This question have 2 different answer depending on what law he is stating in this problem
Solution 1
=> 204 / 32 = 6.38 times did 32 goes to 204.
Solution 2
=> 204 - 32 = 172
=> 172 / 32 = 5.38
=> 5.38 * 100% - 538%

6 0

2 years ago

The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe

WARRIOR [948]

Answer:

7536 $km^3/sec$

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

$Volume = \pi r^2h$

Where $r$ is the radius and

$h$ is the height of cylinder.

As per question statement:

$r$ = 40 km (variable)

$h$ = 2.5 (constant)

$\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h$

As $\pi, h$ are constant:

$\dfrac{dV}{dt} = \pi h\dfrac{d}{dt} r^2\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2 r\dfrac{dr}{dt} \\$Putting the values:$\\\Rigghtarrow\dfrac{dV}{dt} = 3.14 \times 2.5\times 2 \times 40\times 12 \\\Rigghtarrow\dfrac{dV}{dt} = 7536\ km^3/sec$