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Answer:
v = 7.69 x 10³ m/s = 7690 m/s
T = 5500 s = 91.67 min = 1.53 h
Explanation:
In order for the satellite to orbit the earth, the force of gravitation on satellite must be equal to the centripetal force acting on it:
where,
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
Me = Mass of Earth = 5.97 x 10²⁴ kg
r = distance between the center of Earth and Satellite = Radius of Earth + Altitude = 6.371 x 10⁶ m + 0.361 x 10⁶ m = 6.732 x 10⁶ m
v = orbital speed = ?
Therefore,
<u>v = 7.69 x 10³ m/s</u>
For time period satellite completes one revolution around the earth. It means that the distance covered by satellite is equal to circumference of circle at the given altitude.
So, its orbital speed can be given as:
where,
T = Time Period of Satellite = ?
Therefore,
<u>T = 5500 s = 91.67 min = 1.53 h</u>
Answer = 6.24x10^18 x ((2 x 3600) + (47 x 60) + 10)
Answer:
48N
Explanation:
use F=ma, or force is equal to mass multiplied by acceleration.
Till the time car is just adjacent to the bicycle we can say
distance moved by cycle = distance moved by car
Time taken by car to accelerate from rest
Time taken by cycle to accelerate
now the distance moved by cycle in time "t"
distance moved by car in same time
now make them equal
so cycle will move ahead of car for t = 5.68 s