Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
The congruence theorem is always the same
Answer: it’s less 5<10
Step-by-step explanation:
Answer:
f'(x) = 
Step-by-step explanation:
i) f(x) = 9 / x
ii) f'(x) = 
Answer:
18$ fro 3
Step-by-step explanation:
18/3= 6
35/5=7
because 6 is less than 7 you should buy 3 flash drivers it's thebetter deal
