5a+b = 5(6)+3 =3
10-r+5 = 10-(9)+5 =6
Answer:
Step-by-step explanation:
Given that angle A is in IV quadrant
So A/2 would be in II quadrant.
sin A = -1/3
cos A =
(cos A is positive since in IV quadrant)
Using this we can find cos A/2
For this case , the parent function is given by [tex f (x) =x^2
[\tex]
We apply the following transformations
Vertical translations :
Suppose that k > 0
To graph y=f(x)+k, move the graph of k units upwards
For k=9
We have
[tex]h(x)=x^2+9
[\tex]
Horizontal translation
Suppose that h>0
To graph y=f(x-h) , move the graph of h units to the right
For h=4 we have :
[tex ] g (x) =(x-4) ^ 2+9
[\tex]
Answer :
The function g(x) is given by
G(x) =(x-4)2 +9
Answer:
2x+4
Step-by-step explanation:
Given that a is the average (arithmetic mean) of 4x and 7, b is the average of 5x and 6, and c is the average of 3x and 11
By definition of arithmetic mean,
we have
Let us calculate sum of a,b,c in terms of x
a+b+c =
Average = sum/3 =