Methods for graphing lunear equations

Mathematics

1 answer:

Flura [38]2 years ago

6 0

Answer:

Step-by-step explanation:

The first method is by plotting points and then dreaming a line through the points. The second is by using the y intercept and slope the third is applying transformation to the identity function. F(x)=x(x)=x

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A point with a positive x-coordinate and a negative y-coordinate is reflected over the y-axis.

Luden [163]

The x-coordinate is negative, and the y-coordinate is negative.

This is because the y-axis is vertical, so reflecting across it means you will change the sign of the x-value, and the sign of the y-value will stay constant. Since we start off with a positive x and negative y, we will end up with a negative x and negative y.

4 0

2 years ago

I really need help I would appreciate it if someone could help me

sleet_krkn [62]

Answer:

a) The vertex of the graph is $(h,k) = (0, 31)$ , b) $a = -16$ , c) The equation of the parabola is $f(t) = -16\cdot t^{2}+31$ .

Step-by-step explanation:

a) The tennis ball experiments a free fall, that is, an uniform accelerated motion due to gravity and in which effects from Earth's rotation and air viscocity are negligible. The height of the ball in time is represented by a second order polynomial. Hence, the vertex of the parabola is the initial point highlighted in graph.

The vertex of the graph is $(h,k) = (0, 31)$ .

b) If we know that $(h,k) = (0, 31)$ , $f(t) = a\cdot (t-h)^{2} + k$ and $(t,f(t)) = (1,15)$ , then the value of $a$ is: