plasma is a superheated liquid
So, a would-be the correct option.
Answer:
Explanation:
Given that
Mass of bowling ball M1=7.2kg
The radius of bowling ball r1=0.11m
Mass of billiard ball M2=0.38kg
The radius of the Billiard ball r2=0.028m
Gravitational constant
G=6.67×10^-11Nm²/kg²
The magnitude of their distance apart is given as
r=r1+r2
r=0.028+0.11
r=0.138m
Then, gravitational force is given as
F=GM1M2/r²
F=6.67×10^-11×7.2×0.38/0.138²
F=9.58×10^-9N
The force of attraction between the two balls is
F=9.58×10^-9N
B precipitation,condensation,precipitation
Force = 9x10^9 x (6x10^-7 x 6x 10^-7) / (.5)^2
= 0.013 N
Using the formula;
F = 9x10^9 x (Q1 x Q2) / r^2
