Answer:
Explanation:
According to Gausses theorem, electric flux coming out of charge on all sides q is equal to
q / ε₀
q is charge , ε₀ is permittivity of air whose value is given by
8.85 x 10⁻¹²; q = 21.2 x 10⁻⁹ C
Putting the values we get
FLUX =
2.4 x 10³ Nm²/C
To solve this problem we must resort to the Work Theorem, internal energy and Heat transfer. Summarized in the first law of thermodynamics.
Where,
Q = Heat
U = Internal Energy
By reference system and nomenclature we know that the work done ON the system is taken negative and the heat extracted is also considered negative, therefore
Work is done ON the system
Heat is extracted FROM the system
Therefore the value of the Work done on the system is -158.0J
Answer:
The frictional force acting on the block is 14.8 N.
Explanation:
Given that,
Weight of block = 37 N
Coefficients of static = 0.8
Kinetic friction = 0.4
Tension = 24 N
We need to calculate the maximum friction force
Using formula of friction force
Put the value into the formula
So, the tension must exceeds 29.6 N for the block to move
We need to calculate the frictional force acting on the block
Using formula of frictional force
Put the value in to the formula
Hence, The frictional force acting on the block is 14.8 N.
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-Brainly support team (Klara academic DEPT.)Spam words mean team is having trouble determining the question CONTACT For support.
It depends on the circuit. Sometimes it becomes a bit weaker, sometimes it stays the same.