Answer:
CH₃OH + 1.5 O₂ ⇒ CO₂ + 2 H₂O
Explanation:
Let's consider the unbalanced chemical equation for the complete combustion of methanol.
CH₃OH + O₂ ⇒ CO₂ + H₂O
We will balance it using the trial and error method.
First, we will balance H atoms by multiplying H₂O by 2.
CH₃OH + O₂ ⇒ CO₂ + 2 H₂O
Finally, we get the balanced equation by multiplying O₂ by 1.5.
CH₃OH + 1.5 O₂ ⇒ CO₂ + 2 H₂O
<h3>
Answer:</h3>
8.09 × 10²² formula units
<h3>
Explanation:</h3>
Mass of MgCl₂ is 12.8 g
Required to calculate the formula units
1 mole of a compound contains the Avogadro's number formula units
That is;
1 mole = 6.022 × 10²³ formula units
<h3>
Step 1: Calculate the moles of MgCl₂ in 12.8 g </h3>
The molar mass of MgCl₂ is 95.211 g/mol
Number of moles = Mass ÷ molar mass
Moles of MgCl₂ = 12.8 g ÷ 95.211 g/mol
= 0.1344 mole
<h3>Step 2: Calculate the formula units of MgCl₂</h3>
1 mole = 6.022 × 10²³ formula units
Therefore;
Number of formula units = Moles × 6.022 × 10²³ formula units
= 0.1344 mole × 6.022 × 10²³ formula units
= 8.09 × 10²² formula units
Therefore, there are 8.09 × 10²² formula units in 12.8 g of MgCl₂
Answer:
The compound is N2O4
Explanation:
We have certain important pieces of information about the compound;
1) it is an oxide (a binary compound of nitrogen and oxygen)
2) there are no N-N bonds present
3) there are no O-O bonds present
Since it contains only nitrogen and oxygen then nitrogen accounts for 25.9% of the molecule by mass then oxygen should account for (100-25.9) = 74.1% oxygen
Relative atomic mass of oxygen = 16
Relative atomic mass of nitrogen = 14
We now deduce the empirical formula
Nitrogen. Oxygen
25.9/14. 74.1/16
1.85/1.85. 4.6/1.85 (divide through by the lowest ratio)
1 2
Empirical formula is NO2
To find the molecular formula
(NO2)n = 108
(14+2(16))n= 108
46n=108
n= 108/46
n= 2
Therefore molecular formula= N2O4
Answer:
B. their outer electron levels are filled
The answer is the third one
