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Answer:
15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
Step-by-step explanation:
We are to find the derivative of the questions pointed out.
15) K(t) = 5(5^(t)) - 2(3^(t))
Using implicit differentiation, we have;
K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P(w) = 2e^(w) - (2^(w))/5
P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)
Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)
Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
Answer:
20 gray squares
Step-by-step explanation:
Given
See attachment for squares
Required
Number of gray squares when white = 16
First, we calculate the equation that represents both squares.
<u>The white squares</u>
--- initial
-- difference between successive gray squares
So, the nth term is:
<u>The gray squares</u>
--- initial
-- difference between successive gray squares
So, the nth term is:
When the white squares is 16
--- Calculate n
To get the number of gray squares;
Substitute in