Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
As
1/4×100 = 0.25×100
= 25%
Thus,
1/4 = 25%
Step-by-step explanation:
Given the fraction
1/4
- In order to write the fraction 1/4 as a percent, all we need is to multiply 1/4 by 100.
i.e.
1/4×100 = 0.25×100
= 25%
Therefore, we conclude that:
1/4 = 25%
Answer:
area of B or another side tell fast I will answer
Answer:
I think the ans is option 'a'
Final Answer:
Corresponding Angles Theorum; ∠AGF and ∠EHD are congruent
Answer:
28?
Step-by-step explanation:
