Step-by-step explanation:
Solving this equation using the quadratic formula, we get two real solutions :
1.1926 or -4.1926
Now we know the values of v , we can calculate x since x is ∛ v
![x = \sqrt[3]{1.1926} = 1.0605 \\ x = \sqrt[3]{ - 4.1926} = - 1.6125](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%5B3%5D%7B1.1926%7D%20%20%3D%201.0605%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B%20-%204.1926%7D%20%20%3D%20%20-%201.6125)
1.) 9 - c < 2 , C = 7
Graph 7 on the number line.
2.) -3c > 15, C = -5
Graph -5 on the number line.
Hope this helps.
Answer:
3/4
Step-by-step explanation:
A: students present
B: students on time
P(all students present and on time) = P(A and B) = 3/10
P(all students present) = P(A) = 2/5
P(A and B) = P(A).P(B|A) where P(B|A) is the probability of everyone being on time given that everyone is present
So P(B|A) = P(A and B) /P(A) = 3/10 ÷ 2/5 = 3/10 * 5/2 = 15/20 which can be reduced to 3/4 by dividing numerator and denominator by 5
