All categories

3 years ago

7 identities toys weight 1.4kg how much would 3 toys weigh

Mathematics

2 answers:

Studentka2010 [4]3 years ago

4 0

Answer:

0.6 kg or 600 g

Step-by-step explanation:

If 7 (identical) toys weigh 1.4 kg then 1 toy would weigh 1.4 / 7 = 0.2 kg. Therefore, 3 of those same toys weigh 0.2 * 3 = 0.6 kg or 600 g.

Nimfa-mama [501]3 years ago

3 0

Answer:

0.6 kg

Step-by-step explanation:

→ Work out the weight of one toy

7 toys = 1.4 kg

1 toy = 0.2 kg

→ Multiply both sides by 3

3 toys = 0.6 kg

You might be interested in

The sum of two trinomials is 7x2 - 5x + 4. if one of the trinomials is 3x2 + 2x - 1, then what is the other trinomial?

Margarita [4]

Answer:

b. 4x^2 -7x +5

Step-by-step explanation:

When you know a sum and one of its contributors, you can find the other by subtraction. The other trinomial is ...

(7x^2 -5x +4) - (3x^2 +2x -1)

= (7 -3)x^2 +(-5 -2)x +(4 -(-1))

= 4x^2 -7x +5 . . . . . matches B

5 0

1 year ago

7th grade math!

pishuonlain [190]

Answer:

I just learned about this, and if its wrong i am so so sorry

Step-by-step explanation:

a= 120

b= 60

w= 120

x= 120

r= 105

q= 105

p= 105

8 0

2 years ago

Read 2 more answers

Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2

Ipatiy [6.2K]

Answer:

$\frac{dAB}{dt}=340 mil/h$

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:

$AB^{2} =AO^{2}+BO^{2}$ (1)

$AB =\sqrt{AO^{2}+BO^{2}}=$

$AB =\sqrt{90^{2}+120^{2}}=150 miles$

If we take the derivative of the equation (1) we could find the change of the distance between planes.

$2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}$

$2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h$

$\frac{dAB}{dt}=\frac{102000}{150*2}$

Finally,

$\frac{dAB}{dt}=340 mil/h$

I hope it helps you!

6 0

2 years ago

The marker cost 1/3 as a pen.The pen cost 1/3 as much as the book.The book cost 1/3 as much as the game. The price of the marker

creativ13 [48]

Let the price of game, marker, pen and book be $w, x, y and z.

$x = \frac{1}{3} y$
$y = \frac{1}{3} z$
$z = \frac{1}{3} w$
$x = \frac{1}{3} y \\ x = \frac{1}{3} ( \frac{1}{ 3} z) \\ x = \frac{1}{3} ( \frac{1}{3} ( \frac{1}{3} w) \\ x = \frac{1}{27} w$

4 0

2 years ago

Question 1 (Essay Worth 2 points)

tekilochka [14]

Answer:

mu answer is A

Step-by-step explanation:

because if an point shows (0,0) shows the cost is $0 for 0 pound of dog food

hope this helps

4 0

2 years ago

Read 2 more answers