Step 1: Figure out genotypes of parents
Jessica's mom: I^A I^B
Jessica's dad: ii
Step 2: Punnett Square:
( i ) ( i )
(I^A) I^Ai I^Ai
(I^B) I^Bi I^Bi
Step 3: List possible phenotypes
Jessica could be either blood type A (I^Ai) or blood type B (I^Bi)
I would say C. Why I say this is because fur is used to keep an animal warm. If the animal no longer needs to be kept warm, then it no longer needs the thick fur.
<span>An object to be considered alive must have these characteristics.
1. Acquire and uses energy.
2. contains genetic programme.
3. composed of one more cells.
4. Respiration.
5. Must be able to grow.
6. Must be able to reproduce.
7. Must have a metabolism.
8. Must be able to respond to its environment. 9. Must be made of cells.</span>
If pea plant cells contain 14 chromosomes, a pea plant's gamete cell contains 7 chromosomes.
<h3>Describe chromosomes.</h3>
Chromosomes are a pair of thread-like structures that are found in cells.
Re genes and a person's personality are found on the chromosomes.
Meiosis causes the daughter cells to contain half of each chromosome.
<h3>What does a chromosome do primarily?</h3>
Chromosomes' primary role is to transport DNA, which is the building block of all genetic material. DNA contains the genetic instructions for a number of cellular processes. These activities are necessary for the organisms' development, maintenance, and procreation. Chromosomes are shielded by proteins like histones.
To know more about Chromosomes visit:
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Answer:
- time: 1.122 seconds
- range: 10.693 m
- maximum height: 1.543 m
Explanation:
<u>Given</u>:
runner is launched at 30° angle to horizontal at 11 m/s
acceleration due to gravity is g = -9.8 m/s²
<u>Find</u>:
runner's hang time
runner's distance to the landing point
runner's maximum height
<u>Solution</u>:
The (horizontal, vertical) speed components will be ...
(11 m/s)(cos(30°), sin(30°)) = (5.5√3 m/s, 5.5 m/s)
The time of flight can be found from the height formula:
h(t) = 1/2gt² +vt . . . . . . where v is the vertical speed at launch
The time we're concerned with is the time when h(t)=0 and t>0.
0 = -4.9t^2 +5.5√3t = t(-4.9t +5.5√3)
The second factor is zero when ...
t = (5.5√3)/4.9 ≈ 1.122 . . . seconds hang time
__
The distance to the landing point will be the product of horizontal speed and hang time:
d = (5.5 m/s)(5.5√3/4.9 s) ≈ 10.693 m . . . . distance to landing
__
The maximum height can be found from the formula (based on conversion of kinetic energy to potential energy) ...
h = v²/|2g| = (5.5 m/s)²/(2(9.8 m/s²)) ≈ 1.543 m . . . . maximum height