12 23 17 20 14 14 18 16 17 18 18 mean median mode round to the rarest tenth

2 answers:

3 0

The mean is the average. To find this, we add up all the numbers, then divide by the number of numbers there are.
12+23+17+20+14+14+18+16+17+18+18= 187
187/11=17
The mean is 17.

The median is the middle number. To find this, line up all the numbers, smallest to largest.
12, 14, 14, 16, 17, 17, 18, 18, 18, 20, 23
You then cross off numbers from both sides, until you have 1 number remaining.
Your median is 17.

The mode is the number that occurs most frequently.
Your mode is 18.

andreev551 [17]2 years ago

3 0

The median is the middle number of a list of numbers from least to greatest.
I will set up the numbers from least to greatest for you.
12, 14, 14, 16, 17, 17, 18, 18, 18, 20, 23.
To determine a fun way to find the median, cross out the smallest number with the largest number until you can no longer do so.
12, 14, 14, 16,17, 17, 18, 18, 18, 20, 23.
14, 14, 16 ,17, 17, 18, 18, 18, 20.
14, 16, 17, 17, 18, 18, 18.
16, 17, 17, 18, 18.
17, 17, 18.
17.
Your median is 17.
The mode is the number that appears the most within the list of numbers. If we look back from our list of numbers from least to greatest, 18 appears the most.
Your mode is 18.
The mean is the average, in which the sum of all numbers is divided by how many numbers there are.
The sum of the numbers is 187. We have 11 numbers total.
Divide the sum by how many numbers we have in total for the average (mean).
187/11 = 17.
Your mean is 17.
I hope this helps!

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Answer:

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Answer:

a. P(C) = 0.03

P(test+ | C) = 0.89

P(test- | no C) = 0.93

b. Tree diagram is attached.

c. P(test+) = 0.0946

d. P(C | test+) = 0.2822

Step-by-step explanation:

a. Let C denote Lung Cancer The probability that a heavy smoker will develop lung cancer is 3% i.e. 0.03.

If lung cancer is present, the CT scan result comes out to be positive 89% of the times while if lung cancer is not present, the results are negative 93% of the time. Let test+ denote that the test result is positive and test- denote that the test result is negative.

P(C) = 0.03

P(test+ | C) = 0.89

P(test- | no C) = 0.93

b. The first pair of branches represent whether the individual has cancer or not.

P(C) = 0.03

P(no C) = 1 - 0.03 = 0.97

The second pair of branches will represent if the test result came out positive or negative.

For patients with cancer, P(test+) = 0.89, P(test-) = 1 - 0.89 = 0.11

For patients with no cancer, P(test -) = 0.93, P(test+)= 1 - 0.93 = 0.07.

The tree diagram is attached as an image file.

c. P(test+) = P(C)*P(test+| C) + P(No C)*P(test+| No C)

= (0.03)(0.89) + (0.97)(0.07)