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2 years ago

What is 1/5-3/4 help me please i need to step up my grade just a little to get 100%

Mathematics

1 answer:

andriy [413]2 years ago

5 0

-11/20 hope this helps

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X+y=5 3x-4y=8 please i need the steps

grandymaker [24]

Answer:

x + y = 5

3x - 4y = 8

3x + 3y = 15

3x - 4y = 8 -

7y = 7

y = 1

x + y = 5

x + 1 = 5

x = 4

x = 4

y = 1

Hope it helps!

6 0

1 year ago

Help.........................

garri49 [273]

<h3>Answer: Choice A</h3>

$x^2\left(\sqrt[4]{x^2}\right)$

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

$\sqrt[4]{x} = x^{1/4}$

The same applies to x^10 as well

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}$

Multiply the exponents 10 and 1/4 to get 10/4

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}$

$\sqrt[4]{x^{10}} = x^{10/4}$

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

$x^{m/n} = x^a\sqrt[n]{x^b}$

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

$x^{m/n} = x^a\sqrt[n]{x^b}$

turns into

$x^{10/4} = x^2\sqrt[4]{x^2}$

which means

$\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}$

7 0

2 years ago

What is −10−f=−6f+10

sammy [17]

-10-f=-6f+10
-f+6f=10+10
5f=20
F=4

4 0

2 years ago

Find the value of x and the value of y

WARRIOR [948]

I’m pretty sure it’s b.

6 0

2 years ago

Simplify using order of operations 9 divided by 3 + 4 times 3 divided by 6

Alchen [17]

Answer:

$5$

Step-by-step explanation:

$1. \: 3 + 4 \times 3 \div 6 \\ 2. \: 3 + 12 \div 6 \\ 3. \: 3 + 2 \\ 4. \: 5$

7 0

2 years ago