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2 years ago

X-3=10 does anyone know this

Mathematics

1 answer:

vovikov84 [41]2 years ago

5 0

Answer:

Are you trying to solve for x?

x= 13

just kick the 3 to the other side, so a negative 3 would become a positive 3:

x= 10 + 3

x= 13

You can also use cymath it gives you the answer and explanation.

Hope this helps.

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The length of one side of a square is 3n+2. The perimeter of the square is 4(3n+2). Which expression is equivalent to the perime

deff fn [24]

Answer:

4(3n + 2)

Step-by-step explanation:

as we know perimeter of a square is 4 x side

one side is 3n + 2

4 sides = 4(3n +2)

8 0

2 years ago

Rectangle A has 7 times the area of rectangle

krok68 [10]

Wa=0.5Wb, Ha=20, Hb is unkown
the area of rectangle a is : Wa*20
the area of rectangle b is : Wb*Hb
Rectangle a has 7 times the area of rectangle b: Wa*20=7*Wb*Hb
Replace Wa with 0.5Wb: 0.5Wb*20=7Wb*Hb => Hb=10/7

7 0

2 years ago

A boy flying a kite lets out 300 feet of string which makes an angle of 38 degrees with the ground. Assuming that the string is

Lorico [155]

>>>>>>>
>>>>>>>
184.7 ft
>>>>>>>>
>>>>>>>

5 0

3 years ago

Which of these is a simplified form of the equation 7y + 8 = 9 + 3y + 2y? 7y = 6 5y = 17 12y = 17 2y = 1

LekaFEV [45]

7y +8= 9+3y+2y

Combine like terms.

7y+8= 9+5y

Subtract 5y on both sides.

2y+8=9

Subtract 8 on both sides.

2y=1

Your answer is 2y=1

I hope this helps!
~kaikers

4 0

2 years ago

Read 2 more answers

There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student

Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

$\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57$

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0

2 years ago