Hello!
Remember that the symbols: ≤ and ≥ are graphed as a solid line. While the symbols: < and > are graphed as a dotted line.
Also, before graphing, it would be better to convert both equations to slope-intercept form.
y ≤ x + 1 is already in slope-intercept form.
y + x ≤ -1 is not written in slope-intercept form. (Slope-intercept form: y = mx + b)
y + x ≤ - 1 (subtract x from both sides)
y ≤ -x - 1
Graphing those lines, you get the graph below. You can see that Part C best represents the solution set systems of inequalities, because that is where both of the shaded lines intersect.
Answer: Part C
Here is one way to solve for x.
Step 1) 2x^2-7=9
Step 2) 2x^2-7+7=9+7
Step 3) 2x^2=16
Step 4) (2x^2)/2=16/2
Step 5) x^2=8
Step 6) sqrt(x^2)=sqrt(8)
Step 7) |x|=sqrt(8)
Step 8) x=sqrt(8) or x=-sqrt(8)
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Below are explanations/reasons to each of the steps above.
Step 1) Original equation
Step 2) Add 7 to both sides
Step 3) Combine like terms
Step 4) Divide both sides by 2
Step 5) Simplify
Step 6) Apply the square root to both sides. The notation "sqrt" is shorthand for "square root"
Step 7) Use the rule that sqrt(x^2) = |x| for all real numbers x
Step 8) Use the rule that if |x| = k then x = k or x = -k for some fixed number k.
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The two solutions are
x = sqrt(8) or x = -sqrt(8)
m is 43
add my instagarm @jessica.letendre
<span>49.0 units2
1/2 x 7 x 14</span>
Ans: Option (1) <span>
Discontinuity at (1, 7), zero at ( negative four thirds , 0) </span>
Explanation:Given function:
Now if we plug in the x = 1, we would have discontinuity as function goes to infinity.
Now for f(1):
