Answer:
TRUE
Step-by-step explanation:
TRUE
a_1 = 2
a_n = 2*(an_1)
if we start with 2, we would get
a_2 = 2*(a_1) = 2*(2) = 4
a_3 = 2*(a_2) = 2*(4) = 8
a_4 = 2*(a_3) = 2*(8) = 16
a_5 = 2*(a_4) = 2*(16) = 32
.
.
.
and so on
Answer:
The function touches the damping factor
at x= and x=
The x-intercept of f(x) is
at x=
Step-by-step explanation:
Given function is f(x)= and damping factor as y= and y=
To find when function touches the damping factor:
For f(x)= and y=
Equating the both the equation,
x=
For f(x)= and y=
Equating the both the equation,
x=
Therefore, The function touches the damping factor x= and x=
To find x-intercept of f(x):
For x-intercept, y=0
f(x)=
y=
Hence, is always greater than zero.
Therefore,
x=
Thus,
The x-intercept of f(x) is at x=
Plain Z<span> is the </span>plane<span> that is width basicly if looking at a 3d figure.</span>
Answer:
Domain: -3<=x<4
Range:-1<=y<-3
(can I get brainliest please)
Answer:
y = e^x - 4
Step-by-step explanation:
The missing options are
y = ln x - 3
y = ln x - 4
y = e^x - 3
y = e^x - 4
The function is defined in quadrant 3 and increases exponentially, then it is not a logarithm.
f(x) crosses the y-axis at (0, -3). Replacing x = 0 the last option, we get:
y = e^0 - 4 = 1 - 4 = -3