Question

Magnesium hydroxide (Mg(OH)2): g/mol Iron(III) oxide (Fe2O3): g/mol

Answer 1

Molecular mass of Mg(OH)2

= Atomic mass of Mg + 2(Atomic mass of O) + 2(Atomic mass of H)

= 24 g/mol + 2(16 g/mol) + 2(1 g/mol )

= 58 g/mol

Molecular mass of Fe2O3

= 2(Atomic mass of Fe) + 3(Atomic mass of O)

= 2(56 g/mol) + 3(16 g/mol)

= 160 g/mol

Answer 2

Magnesium Hydroxide= 58.33
Iron (III) Oxide= 159.70