No, the cone and the cylinder can't have congruent heights and bases.
<h3>
is it possible that the two cones have congruent bases and congruent heights?</h3>
The volume of a cylinder of radius R and height H is:
V = pi*R^2*H
And for a cone of radius R and height H is:
V = pi*R^2*H/3
So, for the same dimensions R and H, the cone has 1/3 of the volume of the cylinder.
Here, the cylinder has a volume of 120cm³ and the cone a volume of 360cm³, so the cone has 3 times the volume of the cylinder.
This means that the measures must be different, so the cone and the cylinder can't have congruent heights and bases.
If you want to learn more about volumes:
brainly.com/question/1972490
#SPJ1
Answer:
Rock bundles:
950R+250
pop bundles:
1200P+300
Step-by-step explanation:
R=amount of rock bundles
P=amount of pop bundles
Rock bundles:
950R+250
pop bundles:
1200P+300
Answer:
Angle 1 is 112°, 2 is 68°, 3 is 90°, 4 is also 90°, 5 is 22° and angle 6 is 158°
Step-by-step explanation:
To find angles 3 &4 and 2 &1, you subtract the measurement given in each intersection from 180 (all straight lines are 180) to find the other angle measurements. To find 5 I used the 4th angle and the 2nd angle to find the missing number out of 180 since all of the angles in a triangle have a sum of 180°. The missing angle was 22. You can use the angle measurement of #5 to find 6 like how I mentioned before about all straight lines equaling 180°. If this all sounds like mumbo-jumbo I can elaborate a little more in the comment section!
Answer:
you can go on something called tiger algerbra
Step-by-step explanation:
