Since 1 is your initial value you plot a point at (0,1) just like you did , but since your slope (rise/run) is 3, you will go up 3 and over 1, so you will need to graph the point (1,4) instead of (1,-2). Your line will be going up , since a graph is read left to right, you have a positive slope so your line will go up. Hope I helped !
The answer could possibly be -48+11=-37
Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
<h3>
How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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Answer:no he misses the rate he needs to run by 30m seconds
Step-by-step explanation:
45/5=9
Answer:
is linearly dependent set.
Step-by-step explanation:
Given: is a linearly dependent set in set of real numbers R
To show: the set is linearly dependent.
Solution:
If is a set of linearly dependent vectors then there exists atleast one such that
Consider
A linear transformation T: U→V satisfies the following properties:
1.
2.
Here, ∈ U
As T is a linear transformation,
As is a linearly dependent set,
for some
So, for some
Therefore, set is linearly dependent.