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2 years ago

7

A weight suspended from a spring is seen to bob up and down over a distance of 39 cm twice each second. what is its frequency? a

nswer in units of hz.

1 answer:

stira [4]2 years ago

5 0

"Twice each second" means 2 Hz.

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A sled is pulled up to the top of a hill. At thetop of the hill the sled is released from rest and allowed to coastdown the hill

Stolb23 [73]

Answer:

a.) the speed at the bottom is greater for the steeperhill

Explanation:

since the energy at the bottom of the steeper hilis greater

$mgh =\frac{1}{mv^2}$

As we can see from above that v is higher when h ishigher.

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2 years ago

Because energy is conserved, the “lost” energy has actually been changed into other forms. Looking at the two sleds, what effect

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The answer is the kinetic energy of sled B after it crash is 6439j.

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1 year ago

Two plastic balls suspended by strings are placed close to each other. If they have the same charge, how will they interact with

vampirchik [111]

<span>Two plastic balls suspended by strings are placed close to each other. If they have the same charge then they will repel each other.</span>

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2 years ago

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Is the frictional force the same as the applied force when the net force equals zero?

DerKrebs [107]

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Since the net force is to the right (in the direction of the applied force), then the applied force must be greater than the friction force. The friction force can be determined using an understanding of net force as the vector sum of all the forces.

Explanation:

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2 years ago

Air "breaks down" when the electric field strength reaches 3 × 106 n/c, causing a spark. A parallel-plate capacitor is made from

Lera25 [3.4K]

Electric field between the plates of parallel plate capacitor is given as

$E = \frac{Q}{A\epsilon_0}$

here area of plates of capacitor is given as

$A = 0.055 * 0.055$

$A = 3.025 * 10^{-3}$

also the maximum field strength is given as

$E = 3 * 10^6 N/C$

now we will plug in all data to find the maximum possible charge on capacitor plates

$3 * 10^6 = \frac{Q}{3.025 * 10^{-3}*8.85 * 10^{-12}}$

$Q = 8.03 * 10^{-8} C$

so the maximum charge that plate will hold will be given by above

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2 years ago

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