H = –16t2 + 156t + 105, when t = t', the time where the rocket hit the ground after it is launched, so 105= –16t'2 + 156t' + 105, so -16t'2 + 156t' = 0 implies t' =0 or -16t'+ 156= 0, equivalent to t'=9.75, so the answer is
b) <span>9.8 s</span>
I think it’s the bottom one
Don’t open the link the other person put in, it a virus
Answer:
16.8
Step-by-step explanation:
14/20 = 0.7
24 x 0.7 = 16.8
(Feel free to round up or down, or keep it the same depending on the criteria of the question!)
