V₁ = (1/g)₁ = Way₁ = 20(9.81)(0) = 0
V₂ (Vg)₂ = -WAy₂ = -20(9.81)(0.5) = -98.1J
The kinetic energy because the pool rotates about a fixed axis
W = VA/rA = VA/0.2 5VA
Mass momen of inertila about fixed axis which passes through point 0
I₀ = mko² = 50(0.280)² = 3.92 kg. m²
∴ The kinetic energy of the system is
T = 1/2 I₀w² + 1/2mAVA²
= 1/2(3.92)(5VA)² + 1/2 (20) VA² = 59VA²
Now that the system is at rest then T₁ = 0
Energy conservation is
T₁ +V₁ = T₂ + V₂
0+ 0 = 59VA² + (-98.1)
VA = 1.289 m/s
= 1.29 m/s
Answer:
Therefore letter <u>C is the correct answer.</u>
Explanation:
In a projectile motion the total time in the air can be calculated using the following equation:
We analyze the y-component motion.
When the final velocity (v(f)) is equal to zero we calculate the upward time and multiplying it by 2 we find the total time in the air. So we will have:
We can see that the <u>total time is directly proportional to the angle</u>, then when <u>θ increase t increase.</u>
Therefore letter C is the correct answer.
I hope it helps you!
Answer:
False
Explanation:
<em>If one of the bulbs is removed from the series, the other bulb will not come on at all.</em>
This is because the removal of one of the bulbs would interrupt the flow of current though the entire circuit.
Hence, that the other one will get brighter if one of two bulbs in a circuit is removed from its socket is not true.
I will give you more than one , hardness,luster,color,streak,cleavage,fracture.