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2 years ago

Help!!! What’s the approximate sector area

Mathematics

1 answer:

-BARSIC- [3]2 years ago

8 0

Answer:

Step-by-step explanation:

bc itysv coo;

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2. P337. 23. A large box contains 10,000 ball bearings. A random sample of 120 is chosen. The sample mean diameter is 10 mm, and

Rashid [163]

Answer:

B is True

A, C. D are false

Step-by-step explanation:

Given :

Sample size, n = 120

Mean diameter, m = 10

Standard deviation, s = 0.24

Confidence level, Zcritical ; Z0.05/2 = Z0.025 = 1.96

The confidence interval represents how the true mean value compares to a set of values around the mean computed from a set of sample drawn from the population.

The population here is N = 10000

To obtain

Confidence interval (C. I) :

Mean ± margin of error

Margin of Error = Zcritical * s/sqrt(n)

Margin of Error = 1.96 * 0.24/sqrt(120)

Confidence interval for the 10,000 ball bearing :

10 ± 1.96 * (0.24) / sqrt(120)

Hence. The confidence interval defined as :

10 ± 1.96 * (0.24) / sqrt(120) is the 95% confidence interval for the mean diameter of the 10,000 bearings in the box.

4 0

2 years ago

United Blood Services is a blood bank that serves more than 500 hospitals in 18 states. According to their website, a person wit

Anna11 [10]

Answer:

a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

Step-by-step explanation:

I am going to solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Person has type A blood.

Event B: Person has Rh- factor.

43% of people have type O blood

This means that $P(A) = 0.43$

15% of people have Rh- factor

This means that $P(B) = 0.15$

52% of people have type O or Rh- factor.

This means that $P(A \cup B) = 0.52$

a. Find the probability that a person has both type O blood and the Rh- factor.

This is

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

With what we have

$P(A \cap B) = 0.43 + 0.15 - 0.52 = 0.06$

0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b. Find the probability that a person does NOT have both type O blood and the Rh- factor.

1 - 0.06 = 0.94

0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

6 0

2 years ago

If / and / are midsegments of , what can you conclude about / and /? Verify your results by finding x when QR = 3x + 2 and NP =

Ad libitum [116K]

Midsegments are line segments that connect the midpoints of a triangle. If we have the condition that QR = NP, we have the equation
3x + 2 = 2x + 16
Solving for x
3x - 2x = 16 - 2
x = 14
Therefore, x is 14. <span />

8 0

2 years ago

I need some help. Please

Ilya [14]

Are you able to ask your teacher?

7 0

2 years ago

!!PLEASE HELP !!<br> f(x)= |3x+5|+6<br> g(x)= 7<br> Find (f+g)(x).

Svetllana [295]

F(x)=3x+18

That is the awnser they I got

3 0

2 years ago