Answer:
Passive Transport
Explanation:
The three examples of passive transport are
Diffuison
Osmosis
facilated diffuison
So the answer can be A or B
The scientist's results is that at a temperature of 35<span>°C, the solubility of the substance in water is 146.2 grams in 200 grams of water. There isn't really a different method to determine the solubility of a substance in water. Another procedure could be that a lesser amount of the substance is used and the water required to dissolve it is determined. The solubility of the substance based on the two procedures can then be compared.</span>