Answer:
The writer had told about the second road which he doesn't took during his journey. And hence the title is justified.
Explanation:
Answer:
The question is incomplete, here's the complete question;
Black truffles are a unique type of fungi that are highly prized by chefs and food enthusiasts throughout the world. Which of these characteristics is seen in truffles but not in common mushrooms?
a. lack a reproductive phase
b. contains hyphae
c. has spores contained in ascus
d. has spores contained in basidia
Answer is C. Truffles has spores contained in the ascus.
Explanation:
Fungi like yeasts, molds and mushrooms are eukaryotic organisms which acts as main decomposers in the environment. Black truffles are aromatic edible fungi which belong to the ascomycota phylum. They are expensive and normally seen in the southern Europe. The main feature of the ascomycota is the ascus, a sexual spore bearing cell containing spores called ascospores. Black truffles are round shaped with black-brown skin and has small pyramidal cusps. It contains tightly interwoven hyphae (long filament like structure) and numerous asci (spore bearing cells). Each ascus contains some spores called ascopores, which is specific to fungi classified as ascomycetes. Mushrooms belong to the basidiomycota phylum. They are also composed of hyphae and reproduce sexually via the formation of specialized cells called basidia which have spores called basidiospores.
Since we were given only one point, we have to test each exponential function for the point
Since exponential functions are of the form
, The correct option is between option A and option C.
For option A,
On substitution, we have;
.
Since the point satisfied the exponential function
, the exponential function goes through it.
Hence the correct answer is option A.
No need to test for option C again.
Answer:
A. Mendel observed green and yellow pea pods in a 3:1 ratio because the F1 generation was heterozygous.
Explanation:
The two true breeding plants in the parental population were homozygous (that is what true breeding means). Therefore, their cross would lead to all heterozygous offspring (see attached punnet square). Green is the dominant characteristic, so all F1 plants had a green phenotype, but Gg genotype.
The F1 cross would therefore be Gg x Gg. See attached punnet square.
The genotypes in the F2 generation are 1 GG: 2 Gg: 1 gg 1
Therefore, the phenotypic ratio is 3 green pea pods (Gg or GG): 1 yellow (gg)