A₀ = 18 000(1 + 0.0025)⁰
A₁ = 18 000(1 + 0.0025)¹
A₂ = 18 000(1 + 0.0025)²
A(n) = 18 000(1 + 0.0025)ⁿ
So, after 5 months, A(n) = 18 000(1 + 0.0025)⁵ = $18 226.1278 ≈ 18 226.13
5 years is 60 months.
A₆₀ = 18 000(1 + 0.0025)⁶⁰ = $20 909.1021 ≈ $20 909.10
The answer is 5.
Step-by-step explanation:
To find the interquartile range you must look at the median and the upper and lower halves of the data. The median (12) to the upper half of the data (15) is 3. Next, look at the median (12) to the lower half of the data (10) it is 2. We then add 2 and 3 to get the interquartile range of 5.
Answer:
7/10
Step-by-step explanation:
I've attached an image on how you can use the diagram they gave you.
If you color in 7/10s and 7/12s you'll notice that 7/10s is greater.
This is because 1/10 of the whole is greater than 1/12 of the whole.
For 1/10, the whole is being divided into 10, so it equals 0.1.
On the other hand, in 1/12, the whole is being divided by 12, so a part equals 0.083
0.1 is greater than 0.083, so 7 of 0.1 is greater than 7 of 0.083
D= # of dimes
q= # of quarters
QUANTITY EQUATION:
d + q= 64
COST EQUATION:
0.10d + 0.25q= $9.25
STEP 1:
multiply quantity equation by -0.10 to be able to eliminate the d term in step 2
(-0.10)(d + q)= (-0.10)(64)
-0.10d - 0.10q= -6.40
STEP 2:
add equation from step 1 to cost equation to eliminate the d term and solve for q
Add
0.10d + 0.25q= $9.25
-0.10d - 0.10q= -6.40
0.15q= 2.85
divide both sides by 0.15
q= 19 quarters
STEP 3:
substitute q value in step 2 into either original equation to find d value
d + q= 64
d + 19= 64
subtract 19 from both sides
d= 45 dimes
CHECK:
0.10d + 0.25q= $9.25
0.10(45) + 0.25(19)= 9.25
4.50 + 4.75= 9.25
9.25= 9.25
ANSWER: There are 45 dimes and 19 quarters.
Hope this helps! :)
