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2 years ago

How many protons, neutrons, and electrons are there in an atom of potassium-39?

Chemistry

2 answers:

yanalaym [24]2 years ago

6 0

19 - Protons (as the atomic number of proton is 19)
20 - Neutrons (39 minus the amount of protons = the neutrons)

Kamila [148]2 years ago

4 0

Answer:

19 protons, 20 neutrons and 18 electrons. i think

Explanation:

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One reaction involved in the conversion of iron ore to the metal is FeO(s) + CO(g) → Fe(s) + CO2(g) Use Hess’s Law to calculate

Ugo [173]

Answer:

$\delta H_{rxn} = -66.0 \ kJ/mole$

Explanation:

Given that:

$3FeO_3_{(s)}+CO_{(g)} \to 2Fe_3O_4_{(s)} +CO_{2(g)} \ \ \delta H = -47.0 \ kJ/mole -- equation (1) \\ \\ \\ Fe_2O_3_{(s)} +3CO_{(g)} \to 2FE_{(s)} + 3CO_{2(g)} \ \ \delta H = -25.0 \ kJ/mole -- equation (2) \\ \\ \\ Fe_3O_4_{(s)} + CO_{(g)} \to 3FeO_{(s)} + CO_{2(g)} \ \delta H = 19.0 \ kJ/mole -- equation (3)$

From equation (3) , multiplying (-1) with equation (3) and interchanging reactant with the product side; we have:

$3FeO_{(s)} + CO_{2(g)} \to Fe_3O_4_{(s)} + CO_{(g)} \ \delta H = -19.0 \ kJ/mole -- equation (4)$

Multiplying (2) with equation (4) ; we have:

$6FeO_{(s)} + 2CO_{2(g)} \to 2Fe_3O_4_{(s)} + 2CO_{(g)} \ \delta H = -38.0 \ kJ/mole -- equation (5)$

From equation (1) ; multiplying (-1) with equation (1); we have:

$2Fe_3O_4_{(s)} +CO_{2(g)} \to 3FeO_3_{(s)}+CO_{(g)} \ \ \delta H = 47.0 \ kJ/mole -- equation (6)$

From equation (2); multiplying (3) with equation (2); we have:

$3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)} \ \ \delta H = -75.0 \ kJ/mole -- equation (7)$

Now; Adding up equation (5), (6) & (7) ; we get:

$6FeO_{(s)} + 2CO_{2(g)} \to 2Fe_3O_4_{(s)} + 2CO_{(g)} \ \delta H = -38.0 \ kJ/mole -- equation (5)$

$2Fe_3O_4_{(s)} +CO_{2(g)} \to 3FeO_3_{(s)}+CO_{(g)} \ \ \delta H = 47.0 \ kJ/mole -- equation (6)$

$3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)} \ \ \delta H = -75.0 \ kJ/mole -- equation (7)$

$FeO \ \ \ + \ \ \ CO \ \ \to \ \ \ \ Fe_{(s)} + \ \ CO_{2(g)} \ \ \ \delta H = - 66.0 \ kJ/mole$

<u />

$\delta H_{rxn} = \delta H_1 + \delta H_2 + \delta H_3$ (According to Hess Law)

$\delta H_{rxn} = (-38.0 + 47.0 + (-75.0)) \ kJ/mole$

$\delta H_{rxn} = -66.0 \ kJ/mole$

8 0

2 years ago

A 4.5-liter sample of a gas has 0.80 mole of the gas. If 0.35 mole of the gas is added, what is the final volume of the gas? Tem

AVprozaik [17]

Answer:

6.5 liters will be your answer

Explanation:

5 0

2 years ago

Read 2 more answers

A fishing line sinker contains 0.650 moles of lead. How many atoms of lead are in the sinker? Show all of your work, including s

34kurt

Answer:

3.91x10²³ atoms of lead

Explanation:

In chemistry, a mole of a substance is defined as 6.022x10²³ particles that could be atoms, molecules, ions, etc.

As you can see, in the problem, you have 0.650moles of lead in a fishing line sinker, the present atoms are:

$0.650mol Pb \frac{6.022x10^{23}atoms}{1mol}$ =<em> 3.91x10²³ atoms of lead</em>

7 0

2 years ago

How many grams of sodium are needed to produce 12.5g of sodium oxide

Hatshy [7]

Answer:

25 possibly

Explanation:

I'm not too sure about this, but sodium oxide is Na2O, 2 sodium and 1 oxygen, so 12.5g * 2 is 25

If someone else comes up with a more convincing argument listen to them

4 0

2 years ago

A sample of hydraulic acid has a volume of 2.3L. What is the volume of acid in gallons?

Assoli18 [71]

0.60759572 gal is the volume of acid in gallons in a sample of hydraulic acid .

<h3>What do mean by the term "gallons" ?</h3>

The gallon is a unit of measurement for volume and fluid capacity in both the US units and the British imperial systems of measurement.

In SI base units, 1 Gal is equal to 0.01 m/s²

Since ,

1 L, l = 0.2641720524 gal

now, volume of acid in gallons is given by -

2.3 L, l = 2.3 × 0.2641720524 gal

=0.60759572 gal

Hence , 0.60759572 gal is the volume of acid in gallons in a sample of hydraulic acid .

Learn more about gallon ,here:

brainly.com/question/14296555

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7 0

1 year ago

Read 2 more answers