A^2 - b^2 = (a-b)(a+b)
To test it, expand the right hand side.
Answer: {5, -7, -19, -27, -35}
Step-by-step explanation:
In order solve this, we need to plug in the values of x into the table.
For spaces on the left of the equals sign, you need to write each x from the domain. You can then match that x-value with its function value by putting that on the right side.
For each equation, we are simply plugging a number from the domain into the function and replacing the x-value:
I hope this helps. If you need any extra explanation on how the functions are set up, please let me know.
From the diagram associated with this question it can be seen that the first bounce was 1 units high, thus the second bounce is 1 / 2 = 0.5 units high and the third bounce is 0.5 / 2 = 0.25 = 1/4 units high.
Given that B represents the second bounce and C represents the first bounce, the <span>fractions in hundredths that should be written at points B is 0.50 while at point C is 0.25</span>
So the correct statement is:
" The GCF of the numbers in each term in the expression is 2"
<h3>
</h3><h3>
How to rewrite the expression as a product?</h3>
Here we have the expression:
12d - 26c
To rewrite ti as a product, we need to find the greatest common factor between 12 and 26.
The decomposition of these two numbers is:
12 = 2*2*3
26 = 2*13
The greatest common factor between the two numbers is 2, then we can rewrite:
12d - 26c = 2*(6d - 13c)
So the correct statement is:
" The GCF of the numbers in each term in the expression is 2"
If you want to learn more about greatest common factors:
brainly.com/question/219464
#SPJ1
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
Using Heron's Formula we can find the area of the triangle.
A = root (s (s-a) * (s-b) * (s-c))
s = (a + b + c) / 2
Where,
s: semi-perimeter
a, b, c: sides of the triangle
Substituting values:
s = (15 + 16 + 20) / 2
s = 25.5
s = 26
The area will be:
A = root (26 * (26-15) * (26-16) * (26-20))
A = 130.9961832
A = 130 u ^ 2
Answer:
The area of triangle ABC is:
C.
130 u ^ 2