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2 years ago

You are falling off the edge.what should you do to avoid falling..?

2 answers:

6 0

While Mr. SGNU is correct here, you must also shift your weight to your heels using the heelbone as a fulcrum to assist you thrust backwards. Another effective strategy is to simply bend your knees and lean back as if in a limbo. This would create a higher amount of surface area on the ground to assist with friction, thus slowing or stopping your fall. This would give you an effective amount of time to react and move away from the edge.

Nadya [2.5K]2 years ago

3 0

Lean your shoulders back and your waist forwards. Use your arms as a counter weight.

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Your friend is bragging about his motorcycle. He claims that it can go from a stopped position to 50 miles per hour in three sec

andrew-mc [135]

Acceleration because it is at a rise in speed. The formula for acceleration is Speed/Time.

5 0

2 years ago

If your car runs out of gas and you must push it 250 m to the nearest gas station. How much work is done on the car if it is pus

tankabanditka [31]

Answer:

1750 Joules.

Explanation:

Work done = force * distance

= 7 * 250

= 1750 Joules.

6 0

2 years ago

A cat is moving at 18 m/s when it accelerates for 2 seconds. What is its acceleration?

vova2212 [387]

Answer: acceleration: $4 m/s^{2}$

velocity: $26 m/s$

Explanation:

The complete question is written bellow:

A cat is moving at 18 m/s when it accelerates at $4 m/s^{2}$ for 2 seconds. What is his new velocity?

In this situation the following equation will be useful:

$V=V_{o}+at$

Where:

$V$ is the cat’s final velocity (new velocity)

$V_{o}=18 m/s$ is the cat’s initial velocity

$a=4 m/s^{2}$ is the cat's acceleration

$t=2 s$ is the time

Solving the equation:

$V=18 m/s+(4 m/s^{2})(2 s)$

$V=26 m/s$ This is the cat's new velocity

5 0

2 years ago

Which of the following is FALSE about the health benefits of aerobic exercise?

mixer [17]

Answer:

OptionC)

Explanation:

As muscle size increase gradually when we become adolsence and it increases in boys..

6 0

1 year ago

In a fluorescent tube of diameter 4.8 cm , 2.7 × 1018 electrons (with a charge of −e) and 2.4 × 1018 positive ions (with a charg

Lesechka [4]

Answer: 0.817A

Explanation:

Assuming , that one coulomb per second of negative charge alone flow through a conductor and no positive charges flow. I.e Q=It

It means a current of one A flow in the opposite direction.

This is similar to one coulomb per second of positive charge flowing through and there is no negative charge,

In addition, the one coulomb per second of positive charge flows. This is flowing in the current direction of the previous one. Then, the total current is 2 A. Since 2 coulomb of positive charges flow through one due to real positive charge and another due to the negative charge flowing in opposite direction.The charges cannot cancel each other, because even before the current flow the conductor was neutral.

According to this, the current in the given problem is

[2.7 + 2.4] x 10 ^ 18 * 1.602 x 10^ [-19] C/s

= 0.817 A

7 0

3 years ago